Answer
$x\approx-1.532,\ \ -0.347,$ and $1.879$
Work Step by Step
Note that
$f(-2)=-8+6-1=-3$
$f(2)=8-6-1=1$
Since the function is a polynomial, it is continuous everywhere.
$y_{0}=0$ is a value between $f(-2)$ and $f(2)$.
The Intermediate Value theorem guarantees that there exists a $c\in(-2,2)$ for which $f(c)=0$.
Graphing, we find that the roots are (approximately):
$x\approx-1.532,\ \ -0.347,$ and $1.879$
