Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.5 - Continuity - Exercises 2.5 - Page 86: 63

Answer

See the explanation below.

Work Step by Step

No. Take $f(x)=\left\{\begin{array}{lll} 0.5 & for & x\leq 0\\ 1 & for & x\gt 0 \end{array}\right. $and $g(x)=\left\{\begin{array}{lll} 1 & for & x\leq 0\\ 0.5 & for & x\gt 0 \end{array}\right..$ Neither is continuous at x=0 (the one-sided limits are different for each function), but the product is: $h(x)=f(x)\cdot g(x)=\left\{\begin{array}{lll} 0.5 & for & x\leq 0\\ 0.5 & for & x\gt 0 \end{array}\right.$ $h(x)=0.5$, for all x. $h$ is a constant function, continuous everywhere, including at x=0..
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