#### Answer

$w_{xy}=w_{yx}=2y+6xy^2+12x^2y^3$

#### Work Step by Step

Take the first partial derivatives of the given function. When taking a partial derivative with respect to x, treat y as a constant, and vice versa:
$w_x=y^2+2xy^3+3x^2y^4$
$w_y=2xy+3x^2y^2+4x^3y^3$
Then take the derivative of the first order partial derivatives to find second partial derivatives:
$w_{xy}=2y+6xy^2+12x^2y^3$
$w_{yx}=2y+6xy^2+12x^2y^3$