#### Answer

$\dfrac{y}{(1-xy)^2}$ and $\dfrac{x}{(1-xy)^2}$

#### Work Step by Step

We need to take the first partial derivatives of the given function.
In order to find the partial derivative, we will differentiate with respect to $x$, by keeping $y$ as a constant, and vice versa:
$f_x=-(1-xy)^{-2} \times \dfrac{\partial (1-xy)}{\partial x}=\dfrac{y}{(1-xy)^2}$
$f_y=-(1-xy)^{-2} \times \dfrac{\partial (1-xy)}{\partial y}=\dfrac{x}{(1-xy)^2}$