Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Section 14.3 - Partial Derivatives - Exercises 14.3 - Page 807: 1


a) 4x and b) -3

Work Step by Step

a) Apply the chain rule as follows: $\dfrac{∂(2x^2-3y-4) }{∂x}= 4x+0+0=4x$ b) Apply the chain rule as follows: $\dfrac{∂(2x^2-3y-4) }{∂y}= 0-3+0=-3$
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