Answer
$x^{y-1} \space y$ and $x^{y} \space \ln (x)$
Work Step by Step
We need to take the first partial derivatives of the given function.
In order to find the partial derivative, we will differentiate with respect to $x$, by keeping $y$ as a constant, and vice versa:
$f_x=\dfrac{\partial (x^y)}{\partial x}=x^{y-1} \space y$
$f_y=\dfrac{\partial (x^y)}{\partial y}=x^{y} \space \ln (x)$
