## Thomas' Calculus 13th Edition

Published by Pearson

# Chapter 14: Partial Derivatives - Section 14.3 - Partial Derivatives - Exercises 14.3 - Page 807: 29

#### Answer

$f_x=\frac{1}{x+2y+3z}$ $f_y=\frac{2}{x+2y+3z}$ $f_z=\frac{3}{x+2y+3z}$

#### Work Step by Step

Take the first partial derivatives of the given function. When taking a partial derivative with respect to x, treat y and z as constants, with respect to y, treat x and z as constants, and with respect to z, treat x and y as constants: $f_x=\frac{1}{x+2y+3z}\times 1$ $f_y=\frac{1}{x+2y+3z}\times 2=\frac{2}{x+2y+3z}$ $f_z=\frac{1}{x+2y+3z}\times3=\frac{3}{x+2y+3z}$

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