Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Section 14.3 - Partial Derivatives - Exercises 14.3 - Page 807: 8


$f_x=2/3(x^3+y/2)^{-1/3}\times 3x^2$ $f_y=2/3(x^3+y/2)^{-1/3}\times 1/2$

Work Step by Step

Take the first partial derivatives of the given function. When taking a partial derivative with respect to x, treat y as a constant, and vice versa: $f_x=2/3(x^3+y/2)^{-1/3}\times 3x^2$ $f_y=2/3(x^3+y/2)^{-1/3}\times 1/2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.