Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Section 14.3 - Partial Derivatives - Exercises 14.3 - Page 807: 37

Answer

$h_p=sinΦcosθ$ $h_Φ=pcosΦcosθ$ $h_θ=-psinΦsinθ$

Work Step by Step

Take the first partial derivatives of the given function. When taking partial derivative with respect to Φ, treat Φ and θ as constants, with respect to Φ, treat Φ and θ as constants, and with respect to θ, treat p and Φ as constants: $h_p=sinΦcosθ$ $h_Φ=pcosΦcosθ$ $h_θ=-psinΦsinθ$
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