Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 704: 4

Answer

$\lt 5,-7\gt$ and $\sqrt {74}$

Work Step by Step

The magnitude of a vector is:$|n|=\sqrt{n_1^2+n_2^2}$ Since, $u -v=\lt 3,-2 \gt -\lt -2,5 \gt =\lt 5,-7\gt$ and $|\lt 5,-7\gt|=\sqrt{5^2+(-73)^2}=\sqrt {74}$ Hence, we have $\lt 5,-7\gt$ and $\sqrt {74}$
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