Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 704: 10

Answer

$\lt -1,1 \gt$

Work Step by Step

Consider $O$ as origin and let $P$ be the mid-point of segment $RS$. Apply mid-point formula such as:$(\dfrac{x_1+y_1}{2},\dfrac{x_2+y_2}{2})$ $P(\dfrac{x_1+y_1}{2},\dfrac{x_2+y_2}{2})=P(\dfrac{2-4}{2},\dfrac{-1+3}{2})= \lt -1,1 \gt$ $OP=P-O=\lt -1,1 \gt -\lt 0,0 \gt $ or, $OP=\lt -1,1 \gt$
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