Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 704: 11


$\lt -2,-3 \gt$

Work Step by Step

Need to consider two vectors $A$ and $B$. Now, a vector $r$ can be calculated as: $r=B-A=\lt 0,0 \gt -\lt 2,3 \gt=\lt 0-2,0-3 \gt$ $r =\lt -2,-3 \gt$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.