Answer
$0$
Work Step by Step
Since,$A=\lt 1,-1 \gt; B=\lt 2,0 \gt; C=\lt -1, 3 \gt; D=\lt -2,2 \gt$
Now, $\overrightarrow{AB}+\overrightarrow{CD}=\lt 1,-1 \gt \lt 2,0 \gt+\lt -1, 3 \gt \lt -2,2 \gt=\lt 1,1 \gt +\lt -1,-1 \gt=\lt 1-1, 1-1 \gt =0$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 12: Vectors and the Geometry of Space - Section 12.2 - Vectors - Exercises 12.2 - Page 704: 12
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