Answer
$-3{\bf i}+16{\bf j}$
Work Step by Step
If the vector ${\bf v}$ is represented as the directed line segment $\overrightarrow{AB}$ (where the point $A(x_{1},y_{1},z_{1})$ is the initial point, and $B(x_{2},y_{2},z_{2})$ is the terminal point), then
${\bf v}=(x_{2}-x_{1}){\bf i}+(y_{2}-y_{1}){\bf j}+(z_{2}-z_{1}){\bf k}=\langle(x_{2}-x_{1}), (y_{2}-y_{1}), (z_{2}-z_{1}) \rangle$
---
Here,
${\bf v}=(-10-(-7)){\bf i}+(8-(-8)){\bf j}+(1-1){\bf k}$
$=-3{\bf i}+16{\bf j}$
