Answer
$\lt \dfrac{-1}{ \sqrt 2},\dfrac{1}{\sqrt 2} \gt$
Work Step by Step
Since, we have an angle $\theta$ that makes an angle with the line OP and the positive x-axis.
Let us we have the coordinates of a point P on the circle havingradius $r$ are: $(r \cos \theta, r \sin \theta)$
Thus, $\lt \cos (135^{\circ}), \sin (135^{\circ}) \gt=\lt \dfrac{-1}{ \sqrt 2},\dfrac{1}{\sqrt 2} \gt$
