Answer
$3(\dfrac{2}{3}i+\dfrac{1}{3}k-\dfrac{2}{3}k)$
Work Step by Step
Formula to find the unit vector $\hat{\textbf{v}}$ is: $\hat{\textbf{v}}=\dfrac{v}{|v|}$
Given: $v=2i+j-2k$
$|v|=\sqrt{(2)^2+(1)^2+(-2)^2}=\sqrt 9 =3$
Thus, $\hat{\textbf{v}}=\dfrac{2i+j-2k}{3}$
and $v=|v|\hat{\textbf{v}}=3(\dfrac{2}{3}i+\dfrac{1}{3}k-\dfrac{2}{3}k)$
