Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 11: Parametric Equations and Polar Coordinates - Section 11.3 - Polar Coordinates - Exercises 11.3 - Page 663: 55

Answer

$\theta=\pi/4.$

Work Step by Step

Conversion formulas: $\left\{\begin{array}{ll} (x,y)=(r\cos\theta,r\sin\theta) & \\ r^{2}=x^{2}+y^{2}, & \tan\theta=\frac{y}{x} \end{array}\right.$ From this line equation, or, $\qquad y=x,\quad$ we see that: - it passes through the origin - the slope is 1 (that is, $\tan\theta=1$) The whole line is included, (both sides of the pole) so we allow r to be negative. In fact, r can be any number, and $\theta$ can be $\pi/4$, as $\tan(\pi/4)=1$ Thus, a polar equation for this line is $\theta=\pi/4.$
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