Answer
The graph is composed of two parallel lines having slope: $-1$ and one y-intercept is $1$ whereas the other y-intercept is $-1$
Work Step by Step
The conversion of polar coordinates and Cartesian coordinates are described as follows:
1. $r^2=x^2+y^2$ and $r=\sqrt {x^2+y^2}$
2. $\tan \theta =\dfrac{y}{x} \implies \theta =\tan^{-1} (\dfrac{y}{x})$
3. $x=r \cos \theta$ and 4. $y=r \sin \theta$
Given: $r^2+2r^2 \cos \theta \sin \theta)=1$
or, $r^2+2(r \cos \theta) (r \cos \theta)=1$
Thus, the Cartesian equation is $x^2+y^2+2xy=1$
or, $x+y =\pm 1$
or, $y=-x+1$ and $y=-x-1$
Hence, we have the graph is composed of two parallel lines having slope: $-1$ and one y-intercept is $1$ whereas the other y-intercept is $-1$
