Answer
The graph is a circle with center: $(1,-\dfrac{1}{2})$ having radius $\dfrac{\sqrt 5}{2}$.
Work Step by Step
The conversion of polar coordinates and Cartesian coordinates are described as follows:
1. $r^2=x^2+y^2$ and $r=\sqrt {x^2+y^2}$
2. $\tan \theta =\dfrac{y}{x} \implies \theta =\tan^{-1} (\dfrac{y}{x})$
3. $x=r \cos \theta$ and 4. $y=r \sin \theta$
Given: $r^2=2r \cos \theta -r \sin \theta$
Thus, the Cartesian equation is $x^2+y^2=2x-y$
or, $(x-1)^2+(y-\dfrac{1}{2})^2=(\dfrac{5}{4})$
Hence, this shows that the graph is a circle with center: $(1,-\dfrac{1}{2})$ having radius $\dfrac{\sqrt 5}{2}$.