Answer
See image:
Work Step by Step
Conversion formulas: $\left\{\begin{array}{ll}
(x,y)=(r\cos\theta,r\sin\theta) & \\
r^{2}=x^{2}+y^{2}, & \tan\theta=\frac{y}{x}
\end{array}\right.$
The points $(r,\theta)$ of the region are such that:
The angle $2\pi/3$ defines a line through the pole (the origin) with slope $\tan( 2\pi/3) =-\sqrt{3}.$
$2\pi/3$ terminates in the 2nd quadrant, but the directed distance r is negative, so only points in the opposite (4th) quadrant are involved.
Also,
$r \leq -2$ means that these points on the ray are at least two units away from the pole.
The graph is the ray with initial point $(1, -\sqrt{3})$ and slope $-\sqrt{3}$
