Answer
See image:
Work Step by Step
Conversion formulas: $\left\{\begin{array}{ll}
(x,y)=(r\cos\theta,r\sin\theta) & \\
r^{2}=x^{2}+y^{2}, & \tan\theta=\frac{y}{x}
\end{array}\right.$
The points $(r,\theta)$ of the region are such that:
The angle $11\pi/4$ terminates in the 2nd quadrant, as $ 11\pi/4=3\pi/4+2\pi$ defines a line through the pole (the origin) with slope $\tan( 11\pi/4) =-1.$
$11\pi/4$ terminates in the 2nd quadrant, but he directed distance r is partly negative, from -1 to 0, so some points in the opposite (4th) quadrant are involved.
These are points on the line that are at a distance 1 or less from the pole.
For the rest of the values of r, the points represented lie on the ray through the 2nd quadrant.
