Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 13 - Section 13.4 - The Definite Integral: Algebraic Viewpoint and the Fundamental Theorem of Calculus - Exercises - Page 998: 24

Answer

$20$

Work Step by Step

Given: $I=\int_{-4}^4 |-x-2| \ dx$ In order to solve the above integral, we will use the following formula such as: $\int |ax+b| \ dx=\dfrac{1}{2a}(ax+b)|ax+b|+C$ Now, we have $I=-\dfrac{1}{2} [(-x-2)|-x-2|]_{-4}^4 $ or, $=-\dfrac{1}{2}[ [(-4-2)|-4-2|]-[(-(-4)-2)|-(-4)-2|]]$ or, $=-\dfrac{1}{2} \times (-36) +\dfrac{1}{2}(4)$ or, $=20$
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