Answer
$$\frac{1}{2}x^2+\frac{1}{4}x^4+C$$
Work Step by Step
$\int x+x^3$ $dx$
$=\frac{1}{1+1}x^{1+1}-\frac{1}{3+1}x^{3+1}+C$
$=\frac{1}{2}x^2+\frac{1}{4}x^4+C$
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