Answer
$ \displaystyle \frac{2^{x}}{\ln 2}-\frac{3^{x}}{\ln 3}+C$
Work Step by Step
applying Sum and Difference Rules,
... $=\displaystyle \int 2^{x}dx-\int 3^{x}dx$
... both integrals: $\displaystyle \int b^{x}dx=\frac{b^{x}}{\ln b}+C$
$=\displaystyle \frac{2^{x}}{\ln 2}-\frac{3^{x}}{\ln 3}+C$
