Answer
$ 6x-\displaystyle \frac{9}{5x}+C$
Work Step by Step
Expand (multiply out) the integrand,
...$=\displaystyle \int(6x^{4-4}+\frac{9}{5}x^{4-6})dx=\int(6-\frac{9}{5}x^{-2})dx$
... Sum and Difference RuIes,
$=\displaystyle \int 6dx+\int\frac{9}{5}x^{-2}dx$
... Constant MultipIe Rule
$=6\displaystyle \int 1dx+\frac{9}{5}\int x^{-2}dx$
... both integrals: Power Rule, $n\neq-1$
$=6x+\displaystyle \frac{9}{5}\cdot\frac{x^{-1}}{-1}+C$
$=6x-\displaystyle \frac{9}{5x}+C$
