Answer
$ 3.2t+\displaystyle \frac{t^{0.1}}{0.1}+\frac{t^{2.2}}{6.6}+C$
Work Step by Step
Written in exponent form,
applying Sum and Difference RuIes,
...$=\displaystyle \int 3.2dt+\displaystyle \int t^{-0.9}dt+\int\frac{1}{3}t^{1.2}dt$
... Constant Multiple Rule
$=3.2\displaystyle \int 1\cdot dt+\int t^{-0.9}dt+\frac{1}{3}\int t^{1.2}dt$
... Power Rule, all: $n\neq-1$
... first integral: $1=t^{0}$
$=3.2t+\displaystyle \frac{t^{0.1}}{0.1}+\frac{t^{2.2}}{6.6}+C$
