Answer
$2\displaystyle \ln|u|+\frac{1}{8}\cdot x^{2}+C$
Work Step by Step
Written in exponent form,
applying Sum and Difference RuIes,
...$=\displaystyle \int 2u^{-1}du+\displaystyle \int(\frac{1}{4}u)du$
... second integral: Constant MultipIe Rule
$=2\displaystyle \int u^{-1}du+\frac{1}{4}\int udu$
... Power Rule, first: $( n=-1)$
... second: $( n\neq-1)$
$=2\displaystyle \ln|u|+\frac{1}{4}\cdot\frac{x^{1+1}}{1+1}+C$
$=2\displaystyle \ln|u|+\frac{1}{8}\cdot x^{2}+C$
