Answer
$ \displaystyle \frac{x^{3.1}}{6.2}-2.3x+C$
Work Step by Step
applying Sum and Difference RuIes,
...$=\displaystyle \int \displaystyle \frac{1}{2}x^{2.1}dx-\int 2.3dx$
... both integrals: Constant MultipIe Rule
$=\displaystyle \frac{1}{2}\int x^{2.1}dx-2.3\displaystyle \int 1\cdot dx$
... Power Rule, all: $n\neq-1$
... second integral: $1=x^{0}$
$=\displaystyle \frac{1}{2}\cdot\frac{x^{2.1+1}}{2.1+1}-2.3\cdot\frac{x^{0+1}}{0+1}+C$
$=\displaystyle \frac{x^{3.1}}{6.2}-2.3x+C$
