Answer
$-2x^{-1}+\displaystyle \frac{1}{12}\cdot x^{3}+C$
Work Step by Step
Written in exponent form,
applying Sum and Difference RuIes,
...$=\displaystyle \int 2u^{-2}du+\displaystyle \int(\frac{1}{4}u^{2})du$
... Constant MultipIe Rule
$=2\displaystyle \int u^{-2}du+\frac{1}{4}\int u^{2}du$
... Power Rule, both: $( n\neq-1)$
$=2\displaystyle \cdot\frac{x^{-2+1}}{-2+1}+\frac{1}{4}\cdot\frac{x^{2+1}}{2+1}+C$
$=-2x^{-1}+\displaystyle \frac{1}{12}\cdot x^{3}+C$