Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 13 - Section 13.1 - The Indefinite Integral - Exercises - Page 958: 14

Answer

$$ \frac{1}{0.8}x^{0.8}-\frac{1}{1.2}x^{1.2}+C$$

Work Step by Step

$\int (x^{-0.2-x^{0.2}})dx$ $=\frac{1}{-0.2+1}x^{-0.2+1}-\frac{1}{0.2+1}x^{0.2+1}+C$ $= \frac{1}{0.8}x^{0.8}-\frac{1}{1.2}x^{1.2}+C$
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