Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.2 Exponential Functions and Their Derivatives - 6.2 Exercises - Page 418: 43

Answer

$f'(t)=e^{at}(bcosbt)+a sinbt(e^{at})$

Work Step by Step

$f'(t)=\frac{d}{dt}[e^{at}sinbt]$ $=e^{at}\frac{d}{dt}[sinbt]+sinbt\frac{d}{dx}[e^{at}]$ Hence, $f'(t)=e^{at}(bcosbt)+a sinbt(e^{at})$
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