Answer
$0$
Work Step by Step
Need to find the limit for $\lim\limits_{x \to2^{+}}e^{\frac{3}{(2-x)}}$.
Consider $y=\lim\limits_{x \to2^{+}}e^{\frac{3}{(2-x)}}$
when ${x \to 2^{+}}$ then $(2-x) \to 0^{-}$
Thus, $y=\lim\limits_{x \to2^{+}}e^{\frac{3}{(2-x)}}=-\infty$
We have found the fact that
$\lim\limits_{x \to2^{+}}e^{\frac{3}{(2-x)}}=\lim\limits_{y \to-\infty}e^{\frac{3}{(2-x)}}=e^{-\infty}=\frac{1}{e^{\infty}}=0$