## Calculus 8th Edition

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Need to find the limit for $\lim\limits_{x \to \infty}e^{-x^{2}}$. Therefore, $\lim\limits_{x \to \infty}e^{-x^{2}}=\lim\limits_{x \to \infty}\frac{1}{e^{x^{2}}}$ $=\frac{1}{e^{\infty}}=\frac{1}{\infty}$ Hence, $\lim\limits_{x \to \infty}e^{-x^{2}}=0$