Answer
$0$
Work Step by Step
Need to find the limit for $\lim\limits_{x \to \infty}e^{-x^{2}}$.
Therefore, $\lim\limits_{x \to \infty}e^{-x^{2}}=\lim\limits_{x \to \infty}\frac{1}{e^{x^{2}}}$
$=\frac{1}{e^{\infty}}=\frac{1}{\infty}$
Hence, $\lim\limits_{x \to \infty}e^{-x^{2}}=0$