Answer
$(3x^2+x-5)e^x$
Work Step by Step
$\frac{d}{dx}(3x^2-5x)e^x$
$=(3x^2-5x)\frac{d}{dx}(e^x)+e^x\frac{d}{dx}(3x^2-5x)$
$=(3x^2-5x)e^x+e^x(6x-5)$
$=(3x^2-5x+6x-5)e^x$
$=(3x^2+x-5)e^x$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.2 Exponential Functions and Their Derivatives - 6.2 Exercises - Page 418: 33
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