Chapter 6 - Inverse Functions - 6.2 Exponential Functions and Their Derivatives - 6.2 Exercises - Page 418: 33

$(3x^2+x-5)e^x$

Work Step by Step

$\frac{d}{dx}(3x^2-5x)e^x$ $=(3x^2-5x)\frac{d}{dx}(e^x)+e^x\frac{d}{dx}(3x^2-5x)$ $=(3x^2-5x)e^x+e^x(6x-5)$ $=(3x^2-5x+6x-5)e^x$ $=(3x^2+x-5)e^x$

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