## Calculus 8th Edition

$H'(u) = 6u+5$
$H(u) = (3u-1)(u+2)$ Product Rule $H'(u) = (3u-1)(1) + (3)(u + 2)$ Simplify $H'(u) = 3u-1+3u+6$ Simplify $H'(u) = 6u+5$