## Calculus 8th Edition

$y'=\frac{4}{3}\sqrt[3] x+\frac{2}{3}x^{-2/3}$
$y=\sqrt[3] x(2+x)$ Use the product rule. $y'=\sqrt[3] x(1)+(2+x)(\frac{1}{3}x^{-2/3})$ Clean up and simplify. $y'=\sqrt[3] x+\frac{2}{3}x^{-2/3}+\frac{1}{3}\sqrt[3] x$ $y'=\frac{4}{3}\sqrt[3] x+\frac{2}{3}x^{-2/3}$