Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.3 Differentiation Formulas - 2.3 Exercises: 4

Answer

$g'(x)=\frac{7}{2}x-3$

Work Step by Step

$g(x)=\frac{7}{4}x^2-3x+12$ Power Rule $g'(x)=\frac{7}{4}(2)x^{2-1}-3(1)x^{1-1}+0$ Simplify $g'(x)=\frac{7}{2}x-3$
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