Answer
$g'(x)=\frac{7}{2}x-3$
Work Step by Step
$g(x)=\frac{7}{4}x^2-3x+12$
Power Rule
$g'(x)=\frac{7}{4}(2)x^{2-1}-3(1)x^{1-1}+0$
Simplify
$g'(x)=\frac{7}{2}x-3$
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