Answer
$B'(u)=10u^4-16u^3-3u^2+4u-4$
Work Step by Step
$B(u)=(u^3+1)(2u^2-4u-1)$
Use the product rule.
$B'(u)=(u^3+1)(4u-4)+(2u^2-4u-1)(3u^2)$
Distribute.
$B'(u)=4u^4-4u^3+4u-4+6u^4-12u^3-3u^2$
Combine like terms.
$B'(u)=10u^4-16u^3-3u^2+4u-4$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 2 - Derivatives - 2.3 Differentiation Formulas - 2.3 Exercises - Page 140: 26
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