Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.3 Differentiation Formulas - 2.3 Exercises - Page 140: 26



Work Step by Step

$B(u)=(u^3+1)(2u^2-4u-1)$ Use the product rule. $B'(u)=(u^3+1)(4u-4)+(2u^2-4u-1)(3u^2)$ Distribute. $B'(u)=4u^4-4u^3+4u-4+6u^4-12u^3-3u^2$ Combine like terms. $B'(u)=10u^4-16u^3-3u^2+4u-4$
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