Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.3 Differentiation Formulas - 2.3 Exercises: 19

Answer

$G'(q)=-2q^{-2}-q^{-3}$

Work Step by Step

Make an «u» substitution in order to apply the chain rule and make it easier $G(u)=u^2$ $u=1+q^{-1}$ $u'=-q^{-2}$ Derivate $G'(u)=2u*u'$ Undo the substitution $G'(q)=2(1+q^{-1})(-q^{-2})$ $G'(q)=-2q^{-2}-q^{-3}$
This answer is currently locked

Someone from the community is currently working feverishly to complete this textbook answer. Don’t worry, it shouldn’t be long.