#### Answer

$-\frac{12}{(6t-1)^2}$

#### Work Step by Step

$h(t)=\frac{6t+1}{6t-1}$
Use the quotient rule.
$h'(t)=\frac{(6t-1)(6)-(6t+1)(6)}{(6t-1)^2}$
Distribute.
$\frac{36t-6-36t-6}{(6t-1)^2}$
Combine like terms.
$-\frac{12}{(6t-1)^2}$

Published by
Cengage

ISBN 10:
1285740629

ISBN 13:
978-1-28574-062-1

$-\frac{12}{(6t-1)^2}$

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