Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.3 Differentiation Formulas - 2.3 Exercises: 33

Answer

$y'=\frac{t^4-8t^3+6t^2+9}{(t^2-4t+3)^2}$

Work Step by Step

$y=\frac{t^3+3t}{t^2-4t+3}$ Use the quotient rule. $y'=\frac{(t^2-4t+3)(3t^2+3)-(t^3+3t)(2t-4)}{(t^2-4t+3)^2}$ Distribute. $y'=\frac{3t^4+3t^2-12t^3-12t+9t^2+9-2t^4+4t^3-6t^2+12t}{(t^2-4t+3)^2}$ Combine like terms. $y'=\frac{t^4-8t^3+6t^2+9}{(t^2-4t+3)^2}$
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