## Calculus 8th Edition

$y'=-\dfrac{1}{s^2}+\dfrac{3}{2\sqrt{x^5}}$
Reduce the expression $y=\dfrac{s-\sqrt{s}}{s^2}=\dfrac{s}{s^2}+\dfrac{\sqrt{s}}{s^2}$ $y=s^{-1}-s^{-3/2}$ Apply power rule $y'=(-1)s^{-1-1}-(-\dfrac{3}{2})s^{-3/2-1}$ $y'=-s^{-2}+(\dfrac{3}{2})s^{-5/2}$ $y'=-\dfrac{1}{s^2}+\dfrac{3}{2\sqrt{x^5}}$