Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 14 - Partial Derivatives - 14.6 Directional Derivatives and the Gradient Vector - 14.6 Exercises - Page 997: 26

Answer

$\dfrac{3}{5},\lt \dfrac{2}{5},\dfrac{1}{5},\dfrac{2}{5} \gt$

Work Step by Step

Our aim is to determine the maximum rate of change of $f(x,y,z)$.In order to find this, we have : $D_uf=|\nabla f(x,y,z)|$ Given: $f(p,q,r)=arctan(pqr)$ $\nabla f(x,y)=\lt \dfrac{qr}{1+(pqr)^2},\dfrac{pr}{1+(pqr)^2},\dfrac{pq}{1+(pqr)^2} \gt$ From the given data, we have $f(p,q,r)=f(1,2,1)$ Thus, $\nabla f(1,2,1)=\lt \dfrac{2}{5},\dfrac{1}{5},\dfrac{2}{5} \gt$ or, $|\nabla f(1,2,1)|=\sqrt{(\dfrac{2}{5})^2+(\dfrac{1}{5})^2+(\dfrac{2}{5})^2}=\sqrt {\dfrac{9}{25}}=\dfrac{3}{5}$ Therefore, the maximum rate of change of $f(x,y)$ and the direction is:$\dfrac{3}{5},\lt \dfrac{2}{5},\dfrac{1}{5},\dfrac{2}{5} \gt$
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