Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 14 - Partial Derivatives - 14.6 Directional Derivatives and the Gradient Vector - 14.6 Exercises - Page 997: 13

Answer

\[\frac{7\sqrt 5}{10}\]

Work Step by Step

\[g(s,t)=s\sqrt{t}\] Differentiate $g$ with respect to $s$ treating $t$ constant: \[g_s(s,t)=\sqrt{t}\] Differentiate $g$ with respect to $t$ treating $s$ constant: \[g_t(s,t)=\frac{s}{2\sqrt{t}}\] \[g_s(2,4)=\sqrt{4}=2\] \[g_t(2,4)=\frac{2}{2\sqrt{4}}=\frac{1}{2}\] \[\nabla g(2,4)=g_s(2,4)\hat{i}+g_t(2,4)\hat{j}\] \[\nabla g(2,4)=2\hat{i}+\left(\frac{1}{2}\right)\hat{j}\] \[\mathbf{v}=2\hat{i}-\hat{j}\] \[|\mathbf{v}|=\sqrt{2^2+(-1)^2}=\sqrt{5}\] \[\hat{\mathbf{v}}=\frac{\mathbf{v}}{|\mathbf v|}=\frac{2}{\sqrt{5}}\hat{i}-\frac{1}{\sqrt{5}}\hat{j}\] Required derivative is given by: \[D_{\mathbf v}g(2,4)=\nabla g(2,4)\cdot \hat{\mathbf v}\] \[D_{\mathbf v}g(2,4)=\left[2\hat{i}+\left(\frac{1}{2}\right)\hat{j}\right]\cdot\left[\frac{2}{\sqrt{5}}\hat{i}-\frac{1}{\sqrt{5}}\hat{j}\right]\] \[D_{\mathbf v}g(2,4)=\frac{4}{\sqrt{5}}-\frac{1}{2\sqrt{5}}=\frac{7\sqrt{5}}{10}\]
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