Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 14 - Partial Derivatives - 14.6 Directional Derivatives and the Gradient Vector - 14.6 Exercises - Page 997: 11

Answer

$$\dfrac{4-3\sqrt 3}{10}$$

Work Step by Step

Our aim is to determine the directional derivative. In order to find it we have to use the expression: $D_uf(x,y)=f_x(x,y)m+f_y(x,y)n$ or, $D_uf(x,y)=\nabla f(x,y) \cdot u=\nabla f(x,y) \cdot \dfrac{v}{|v|}$ Given: $f(x,y)=e^x \sin y$ $D_uf(x,y)=(e^x \sin y) \times \cos (\pi/3)+(e^x \sin y) \times \sin (\pi/3)$ From the given data, we have : $(x,y)=$ $(0,\dfrac{\pi}{3})$ $D_uf (0,\dfrac{\pi}{3})=(\dfrac{-6}{10})(\dfrac{\sqrt 3}{2})+(\dfrac{8}{10})(\dfrac{1}{2})=\dfrac{4-3\sqrt 3}{10}$
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