Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 14 - Partial Derivatives - 14.6 Directional Derivatives and the Gradient Vector - 14.6 Exercises - Page 997: 24

Answer

$\dfrac{\sqrt {17}}{2}, \lt 0,\dfrac{1}{2},2 \gt$

Work Step by Step

Our aim is to determine the maximum rate of change of $f(x,y)$.In order to find this, we have : $D_uf=|\nabla f(x,y)|$ Given: $f(x,y,z)=x \ln (yz)$ $\nabla f(x,y,z)=\lt \ln (yz)y , x/y,x/z \gt $ From the given data, we have $f(x,y,z)=f(1,2,\dfrac{1}{2})$ $\nabla f(1,2,\dfrac{1}{2})=\lt \ln 1, 1/2,2 \gt=\lt 0,\dfrac{1}{2},2 \gt$ $|\nabla f(1,2,\dfrac{1}{2})|=\sqrt{0^2+(\dfrac{1}{2})^2+2^2}=\dfrac{\sqrt {17}}{2}$ Therefore, the maximum rate of change of $f(x,y)$ and the direction is: $\dfrac{\sqrt {17}}{2}, \lt 0,\dfrac{1}{2},2 \gt$
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