Answer
$$ y'=16^ {\sin x} \cos x\ln 16.$$
Work Step by Step
Recall that $(a^x)'=a^x\ln{a}$
Recall that $(\sin x)'=\cos x$.
Since $ y=16^{\sin x}$, then by the chain rule, we have
$$ y'=16^ {\sin x} \cos x\ln 16.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 343: 48
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