Answer
$\frac{3^{x}}{\ln 3} +c $
Work Step by Step
Let $ u=3^x $, then $ du= 3^x \ln 3 dx $ and hence
$$\int3^xdx = \frac{1}{\ln 3}\int du +c=\frac{1}{\ln 3}u +c\\
=\frac{1}{\ln 3}3^x +c =\frac{3^{x}}{\ln 3} +c. $$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 343: 102
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