Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 343: 104


$$ \frac{3^{\sin x}}{\ln 3} +c. $$

Work Step by Step

Let $ u= 3^{\sin x}$, then $ du=\ln 3 \cos x 3^{\sin x} dx $ and hence $$\int \cos x 3^{\sin x}dx =\frac{1}{\ln 3} \int du +c= \frac{3^{\sin x}}{\ln 3} +c. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.