Answer
$$ y'
=\frac{4x+11}{(x+1)(2x+9)}$$
Work Step by Step
Recall that $(\ln x)'=\dfrac{1}{x}$
Recall the product rule: $(uv)'=u'v+uv'$
Since $ y=\ln((x+1)(2x+9))$, by using the chain rule and the product rule, we have
$$ y'=\frac{(x+1)'(2x+9)+(x+1)(2x+9)'}{(x+1)(2x+9)}\\
=\frac{(1)(2x+9)+(x+1)(2)}{(x+1)(2x+9)}=\frac{4x+11}{(x+1)(2x+9)}$$
